Topic 1.4 · both courses, SL and HL

It grew to 1628.89 and buys 1212.03 of things.

Compound interest, depreciation, and the real value question that is on the syllabus and almost never taught.

1000 invested at 5% a year, with inflation running at 3%. Run the years and watch the three lines separate.

10 years
1500.00simple
1628.89compound
1212.03real value

Compound beats simple. Inflation beats both.

The formula

FV = PV (1 + r100k)kn where k is the number of compounding periods a year: 1 yearly, 4 quarterly, 12 monthly. Your calculator has this built in; the marks are for choosing k and n correctly, not for the arithmetic.

1000, 5%, 10 yr→ simple: 1000 + 500 = 1500 → compound yearly: 1628.89 quarterly→ 1643.62 monthly→ 1647.01 daily→ 1648.66 and it stops there

More frequent compounding pays, but it runs out of road. Yearly to monthly gains 18.12; monthly to daily gains 1.65; and no frequency ever beats 1648.72. Compounding more often is worth far less than people assume.

Depreciation is the same formula

60000 baht, −15%, 5 yr→ 60000 × 0.85⁵ = 26,622.32

Use 0.85, not −15. A 15% fall leaves 85% behind, and the multiplier is what goes in the power. Note also that it never reaches zero: percentage decline always leaves something.

Real value, which is the examinable part people skip

Divide by the inflation factor. After 10 years at 3%, prices are 1.0310 times higher, so your 1628.89 buys 1628.89 ÷ 1.0310 = 1212.03 of what you could have bought on day one.

The real growth rate is 1.051.03 − 1, about 1.94% a year, not 2%. Close, but it is a ratio and not a subtraction.

Worked example

A family puts 250,000 baht into an account paying 4.5% a year, compounded monthly. Inflation runs at 2.5% a year.

What is it worth after 7 years, and what can it actually buy?

Your turn

1. 1000 at 5% compounded yearly for 10 years, to 2 decimal places.

2. A 60,000 baht motorbike depreciates 15% a year. Its value after 5 years, to 2 decimal places.

3. Interest is 5% and inflation is 5%. After ten years your money:

Where the marks go

Getting k and n right. Monthly for 10 years is k = 12 and n = 10, giving 120 periods; putting 120 in both places is the classic wreck.

Using the multiplier for depreciation, 0.85 rather than −15.

Dividing by the inflation factor when real value is asked for, and saying what the answer means: the money grew and still buys less.

Come back to this

These three are deliberately not all about this page. In an examination the hardest step is deciding which method applies, and questions that arrive straight after the method never make you decide. Answer from memory before you reveal anything.

Come back to these in a week, and again in a month.

  1. Which method?

    A motorbike worth 60,000 baht loses 15% of its value each year. What is it worth after 5 years?

    Depreciation, the same formula with a multiplier under 1. 60000 × 0.85⁵ = 26,622.32 baht. Use 0.85, never −15.
  2. Which method?

    A sequence begins 2, 5, 8, 11. What is its 50th term?

    Arithmetic. 2 + 49(3) = 149. Equal differences, so add; no repeated percentage anywhere.
  3. Which method?

    Interest is 5% and inflation is 5%. After ten years, has your money gained?

    Real value. The two factors cancel exactly, so it buys precisely what it did at the start despite the number growing 63%.
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