Topic 1.3 · both courses, SL and HL

Same start, same second term, 51 times apart.

Adding against multiplying, and the sum that stops at a number however long you keep going.

Both sequences begin 3, 6. One keeps adding 3, the other keeps multiplying by 2. Nothing else differs. Step through n.

n = 1
3adding 3
3× 2 each time
equaltimes bigger

Identical for two terms. After that they are not comparable at all.

The formulae

un = u₁ rn−1, the same minus one as the arithmetic case, and for the same reason.

Sn = u₁(rn − 1)r − 1. When r is less than 1, flip both differences to keep everything positive: u₁(1 − rn)1 − r.

u₁ = 3, r = 2 3, 6, 12, 24, 48, … u₅= 3 × 2⁴ = 48 u₁₀= 3 × 2⁹ = 1536 S₁₀= 3(2¹⁰ − 1)1 = 3069

When r is less than 1

The terms shrink, and the running total climbs towards a ceiling it never touches. With u₁ = 4 and r = 0.5:

S₁₀= 7.9922 S₂₀= 7.999992 S∞= u₁1 − r = 40.5 = 8

The shortfall is always 8 × rn. At n = 10 that is 8/1024, which is why S₁₀ is 7.9922 and not 8. The sum to infinity exists only when |r| < 1; outside that the terms do not shrink and there is nothing to converge to.

Worked example

A rumour starts with 3 people on Monday. Each day, every person who knows it tells 2 new people.

How many people hear it on the seventh day, and how many know it in total by then?

Your turn

1. u₁ = 3 and r = 2. Find u₁₀.

2. Find the sum of the first 10 terms.

3. u₁ = 4 and r = 0.5. Find the sum to infinity.

Where the marks go

Finding r by dividing consecutive terms, not subtracting. Subtracting gives d and is the commonest way to start a geometric question wrongly.

The n − 1 in the power, checked by putting n = 1 back in.

Stating |r| < 1 before using the sum to infinity. It is a condition, not a formality, and questions are set where it fails.

Come back to this

These three are deliberately not all about this page. In an examination the hardest step is deciding which method applies, and questions that arrive straight after the method never make you decide. Answer from memory before you reveal anything.

Come back to these in a week, and again in a month.

  1. Which method?

    A sequence begins 5, 8, 11. Find the sum of the first 20 terms.

    Arithmetic. Equal differences of 3, so Sₙ = (n/2)(u₁ + uₙ) = 10(5 + 62) = 670. Dividing consecutive terms here gives no constant ratio, which rules out geometric.
  2. Which method?

    A ball dropped from 2 m rebounds to 0.8 of its height. How far does it travel in total?

    Infinite geometric, and the doubling. 2 + 2(1.6/0.2) = 18 m. The first drop happens once; every rebound is travelled twice.
  3. Which method?

    Find the percentage error in using 3.14 for π.

    Percentage error, dividing by the exact value: |3.14 − π|/π × 100 = 0.0507%.
The same idea elsewhere

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