Year 8 · Unit 6 · Lesson 5 · teacher page

Teaching: steady rate, straight line

The new idea is that rate is a property of a graph, its steepness measured as rise over run, with a unit. Students who know y = kx already have the rule; here they meet it as slope between any two points.

Number and AlgebraNo calculator

At a glance. One lesson of about 60 minutes. Students read a rate from two points as rise over run, say its units, compare lines by steepness, and use the rate to find values and times.

Calculator: no calculator. Every rise and run divides exactly or to a simple decimal, and the work is reading the graph and naming the unit.

What students will learn

Know

  • The rate of a straight line is rise ÷ run between any two points.
  • Its unit is the unit up the side per the unit across.
  • On the same scales, a steeper line is a greater rate.

Understand

  • The rate is the same at every point on a line, so any pair of points will do.
  • The height of the end point is a total, not a rate.
  • A change of units on either axis changes the number and the unit of the rate.

Do

  • Find a rate from two points on a line.
  • Compare two lines and say which has the greater rate.
  • Use the rate to find a value or a time.

MYP assessment criteria

Wording paraphrased. What this lesson gives you evidence for, and what to look for:

The one thing to do with the figure

Ask for a prediction before the sliders move. “Kofi is 36 km out after 3 hours and Ana is 27 km out. Which line is steeper?” Take a sketch from each pair on mini whiteboards before the figure appears.

Then set the run to 1, 2, 3 and 4 and ask for the rise each time, before the readout. Ask students to predict rise ÷ run, and what that says about the rate at different points on the line.

A possible order

5 minWarm-up from the student page, in silence, then answers.
10 minHook: Kofi and Ana, with sketches on whiteboards. The figure on the board.
10 minKey idea; rise and run named on the sketch; the unit of the rate.
10 minWorked examples; students finish the faded example in pairs.
5 minQuestion 1, the check. If many choose B, C or D, return to rise and run on the figure.
15 minYour turn, Levels 1 to 3, at each student's own pace.
5 minExit ticket, question 9, on paper or on screen.

The answers

Warm-up6; 60 km per hour; (4, 20).
HookKofi 12 km per hour, Ana 9 km per hour.
Worked example 14.5 litres per minute.
Worked example 263 litres after 14 minutes; 8 minutes for 36 litres.
Faded example7 litres per minute.
1. Rate from a pointA, 14 km per hour. B, C and D combine the coordinates by adding, multiplying or subtracting.
2. Rate from a point13. 78 ÷ 6 = 13 litres per minute.
3. The unit of a rateA. B has the units inverted; C subtracts; D multiplies.
4. Which line is steeperA. P has rate 9 and Q has rate 6. B and D reward the bigger x; C looks at the height only.
5. Rate from two points17. (102 − 34) ÷ (6 − 2) = 68 ÷ 4 = 17.
6. Time to reach an amount9. 24 ÷ 3 = 8 litres per minute, and 72 ÷ 8 = 9 minutes.
7. A less steep line25. Rate of A is 8, rate of B is 5, and 5 × 5 = 25.
8. Reading with unit changes18. 300 m per minute × 60 = 18000 m per hour = 18 km per hour.
9. Where the line endsB. A: reads the end height as the rate. C: both lines through the origin are not equal. D: the right answer for the wrong reason.

What each wrong answer tells you

They giveWhat it usually meansWhat to do
B, C or D in question 1; 84 or 468 in question 2Added, multiplied or subtracted the coordinates.Ask what the rise is and what the run is, then write rise ÷ run.
B, C or D in question 3Mixed up the units, or combined them with the wrong operation.Write the units next to the numbers: 18 m, 6 s.
B or D in question 4Took the larger x as steeper.Ask how far up each line goes in one step across.
68, 34 or 4 in question 5Gave the rise only, divided by the wrong x, or gave the run only.Ask for a rise and a run in a table, then divide.
576 or 64 in question 6Multiplied or subtracted the amount and the rate.Say “how many 8s make 72?”.
37 or 15 in question 7Applied the difference to the height, or gave the gap.Ask students to write the rate of each line first.
300, 0.3 or 7500 in question 8Stopped at metres per minute, or at km per minute, or multiplied.Underline the unit asked for, and change one unit at a time.
A or D in question 9Used the end height or the end x as the rate.Divide each end height by its x value and compare.

Questions worth asking

Differentiation

A way in for anyone stuck

Stretch

Students learning in English as an additional language

Several words have everyday meanings. Show “rise” and “run” with a hand going up and then across on a staircase.

WordPlain meaningExample
rate of changehow much one quantity changes for one step of another20 litres per minute
steeprising quickly for each step acrossthe steeper line is the faster
risehow far a line goes up between two points15 litres
runhow far a line goes across between two points3 minutes
constantstaying the samea constant speed
originthe point (0, 0)where the axes meet

Sentence starters for explaining aloud or in writing:

Two things not to say

“Slope is rise over run, learn it.” Start from kilometres in each hour; the formula is the shorthand.

“The line that is higher is the faster.” Only on the same time scale, and only at the end of the same time.

Questions to set

Extra practice in three tiers, including one question from earlier work for spacing. Every answer has been checked.

1Fluency

The idea on its own, with friendly numbers. Set these first.

  1. ReadingA line through the origin passes through (4, 28). What is its rate?
    7 per unit across: 28 ÷ 4 = 7.
  2. UsingA line through the origin has a rate of 6 km per hour. How far is it at 5 hours?
    30 km.

2In context

The same idea inside a situation, where the first job is deciding what to calculate.

  1. Two pointsA graph through the origin passes through (2, 30) and (5, 75). What is the rate?
    (75 − 30) ÷ (5 − 2) = 45 ÷ 3 = 15.
  2. UnitsA plant's height in cm against days is a line through the origin and (10, 35). Give the rate in cm per day and in mm per day.
    3.5 cm per day, which is 35 mm per day.
  3. Earlier work (Lesson 3)Change 126 km per hour to metres per second.
    35 metres per second: 126 ÷ 3.6 = 35.

3Challenge

Reasoning, generalizing and working backwards.

  1. ReasoningA line through the origin has a rate of r, and another has 2r. Where is the second line at x = 3 compared with the first at x = 6?
    The same height: 2r × 3 = 6r.
  2. SpottingA graph of cost in rupees against kilograms passes through (2, 5) and (6, 15). Is it a line through the origin? How can you tell?
    Yes: the rate is 10 ÷ 4 = 2.5, and 2.5 × 2 = 5, so the line passes through (0, 0).

Practicalities

Works on a phone or a shared screen. Nothing a student types is saved or sent anywhere.

All three sliders work with the keyboard (tab to a slider, then the arrow keys) and by touch. Under the figure, “Show me the steps” gives the same states in words.

No device? Plot the two journeys on squared paper and mark the rise and the run with a ruler.