Year 7 · Unit 3 · Lesson 3 · teacher page

Teaching: how do you find the 100th term?

Build both rules from the same bars, make the number in front of n the step, and use undoing to test whether a number is in the sequence.

Number and AlgebraNo calculator

At a glance. One lesson of about 60 minutes. Students write a term-to-term rule and a position rule for a linear sequence, use the position rule to find any term, and undo it to test whether a number is a term.

Calculator: no calculator. Nothing here needs one. The multiplications are small, and the structure of the rule is the point.

What students will learn

Know

  • The term-to-term rule says how to get the next term from the one before.
  • The position rule gives a term from its position n.
  • In a linear sequence the number in front of n is the step.

Understand

  • A position rule jumps to any term; a term-to-term rule needs the term before.
  • The constant in the position rule corrects the first term.
  • Undoing the rule tells you whether a number is in the sequence, and where.

Do

  • Find a position rule for a linear sequence and test it on the first terms.
  • Use a position rule to find a far term.
  • Decide whether a given number is a term and give its position.

MYP assessment criteria

Wording paraphrased. What this lesson gives you evidence for, and what to look for:

The one thing to do with the figure

Change the step first, then the first term. Ask what happens to the position rule each time, before reading it off. The step goes in front of n; the first term moves the number at the end.

Use the second figure for one question only: “is it a whole number of steps?”. Have students predict yes or no for N before sliding, and say why.

A possible order

5 minWarm-up from the student page, in silence, then answers.
10 minHook and the first figure, with predictions first.
10 minKey idea; the second figure on testing membership.
10 minWorked example on the 40th term; students finish the faded one in pairs.
5 minQuestion 1, the check. If many choose A or C, go back to the first figure and test n = 1.
15 minYour turn, Levels 1 to 3, at each student's own pace.
5 minExit ticket, question 9, on paper or on screen.

The answers

Warm-up7; 17; 63.
Worked example5n + 4, so the 40th term is 204.
Faded example6n − 4, so the 25th term is 146.
1. Position rule from a sequenceB, 4n + 2. A uses the first term as the constant; C swaps the step and the constant; D leaves out the step.
2. Using a position rule23. 5 × 4 + 3.
3. Using a term-to-term rule37. 2 + 5 × 7 = 37.
4. A far term from the position rule199. 4 × 50 − 1.
5. Which term23. (117 − 2) ÷ 5 = 23.
6. Is it a termB, 83. Add 1 and divide by 6: only 84 ÷ 6 is a whole number. 80, 88 and 91 give 13.5, 14.8 and 15.3.
7. First term past a target202. The 28th term is 195, the 29th is 202.
8. Working backwards along a sequence3. The step is 5. 23 − 4 × 5 = 3.
9. The step is not the whole ruleB. A takes the step as the whole rule; C and D put the wrong number in front of n.

What each wrong answer tells you

They giveWhat it usually meansWhat to do
A, C or D in question 1Used the first term or the term number as part of the rule, or left out the step.Ask for the step first, then test n = 1 in every option.
20 or 35 in question 2Dropped the +3, or added before multiplying.Write the rule with the steps in order: multiply n by 5, then add 3.
42 or 30 in question 3Multiplied the term number by the step, or stopped one term early.Number the terms in a row: 1st, 2nd, up to the 6th. How many steps are there?
200 or 203 in question 4Left out the constant, or counted 50 steps from the first term.Use the rule itself on n = 1 to see what it must give. From the 1st term to the 50th is 49 steps.
22 or 17 in question 5Found the number of steps, not the term number, or divided by the first term.Undo the rule step by step in a flow of boxes.
A, C or D in question 6Tested divisibility by the first term or by the step alone.Say: subtract the constant, then divide by the step. Is it whole?
195 or 209 in question 7Gave the term on either side of the one needed.Write the 28th, 29th and 30th terms and compare each with 200.
18 or 8 in question 8Counted the wrong number of steps back.Draw the five terms and put the step between each pair of neighbours.

Questions worth asking

Differentiation

A way in for anyone stuck

Stretch

Students learning in English as an additional language

The word position is used in a mathematical sense here. Point at the place under each bar and say “position one, position two”. Term, rule and step also need a picture.

WordPlain meaningExample
term-to-term rulesays how to get from one term to the nextadd 4
position rulegives a term from its position n4n + 1
positionthe place of a term in the sequence, counting from 110 is in position 2 of 5, 10, 15
stepthe amount added each time4 in 5, 9, 13
linear sequencea sequence with the same step every time3, 7, 11, 15
testcheck a rule on a case you already know4 × 1 + 1 = 5

Sentence starters for explaining aloud or in writing:

Two things not to say

“The rule is the number you add.” The step is only half the rule. Always test n = 1.

“Just keep adding on your calculator.” That is fine for the 8th term and useless for the 200th. The position rule is the point of the lesson.

Questions to set

Extra practice in three tiers, including one question from earlier work for spacing. Every answer has been checked.

1Fluency

The idea on its own, with friendly numbers. Set these first.

  1. Term-to-termWrite the next two terms of 11, 15, 19, 23, …
    27, 31.
  2. Position ruleUse the position rule 6n − 2 to find the 5th term.
    28. 6 × 5 = 30, then 30 − 2.

2In context

The same idea inside a situation, where the first job is deciding what to calculate.

  1. ContextA cyclist rides 12 km on the first day and 5 km more each day than the day before. How far does she ride on day 9?
    52 km. 12 + 8 × 5.
  2. Earlier work, powersWrite the first four square numbers, and the gaps between them. Is the sequence linear?
    1, 4, 9, 16; gaps 3, 5, 7. Not linear.

3Challenge

Reasoning, generalising and working backwards.

  1. ReasoningThe 3rd term of a linear sequence is 17 and the 8th term is 42. Find its position rule.
    The step is 25 ÷ 5 = 5, and 5n + 2 gives 17 and 42. So 5n + 2.
  2. Is it a termIs 300 a term of 4n + 2? Explain.
    No. 300 − 2 = 298, and 298 ÷ 4 = 74.5 is not whole.

Practicalities

Works on a phone or a shared screen. Nothing a student types is saved or sent anywhere.

Both figures work with the keyboard (tab to a slider, then the arrow keys) and by touch. Under each one, “Show me the steps” gives the same states in words.

No device? Write the terms on strips of paper and fold them to show the steps.