Year 11 Extended · Unit 6 · Lesson 7 · teacher page

Teaching: quadratic inequalities and sign diagrams

Students can solve quadratic equations and linear inequalities. This lesson joins the two: the roots become the critical values, and a sign diagram answers which regions satisfy the inequality.

Number and AlgebraNo calculator

At a glance. One lesson of about 60 minutes. It assumes factorizing and the quadratic formula from Year 10. Students solve a quadratic inequality using the roots and the direction of the parabola, handle a negative leading coefficient, count integer solutions, and use the discriminant to bound a coefficient.

Calculator: no calculator. No calculator: the roots are rational and the reasoning is the sign diagram. A graphing calculator is used in the next lesson to check graphically.

What students will learn

Know

  • A quadratic changes sign only at its roots.
  • For a positive leading coefficient the quadratic is below zero between the roots and above outside them.
  • No real roots means the discriminant is negative.

Understand

  • Why the sign can be read from the opening direction and the roots.
  • Why dividing by x loses solutions.
  • Why a strict inequality excludes the roots and a non-strict one includes them.

Do

  • Solve a quadratic inequality exactly.
  • Count integer solutions in an interval or a union.
  • Use the discriminant to find the values of a parameter.

MYP assessment criteria

Wording paraphrased. What this lesson gives you evidence for, and what to look for:

The one thing to do with the figure

Ask for the prediction first. Then keep the roots fixed and flip the direction, and ask which parts of the strip change colour and why the roots themselves do not.

Ask: “What happens to the strip if the two roots move closer together?” The middle region narrows, and with a gap of 1 it holds no whole number.

A possible order

5 minWarm-up from the student page, in silence, then answers.
5 minHook: the tea stall; collect predictions for the range of cups.
12 minFigure, key idea and warning card; sketch each parabola next to its sign strip.
8 minWorked examples; pairs finish the faded example.
5 minQuestion 1, the check. If many choose A, ask where the parabola is above the axis.
20 minYour turn, Levels 1 to 3, at each student's own pace.
5 minSomething to think about, then the exit ticket, question 8.

The answers

Warm-up(x + 7)(x − 3); 4 or 5; x < −3.
HookP = −(x − 2)(x − 6), which is positive for 2 < x < 6, so between 200 and 600 cups. The most profit is half way, at x = 4 (400 cups), where P = 4.
Worked examples−3 < x < 4; x ≤ −3 or x ≥ 0.5; −2 ≤ x ≤ 5.
Faded examplex < −5 or x > 3.
1. Reading a quadratic inequalityB. A is the region below zero; C drops one side; D has the roots' signs wrong.
2. Counting integer solutions7. 0 to 6.
3. Largest integer in a solution4. −7 ≤ x ≤ 4.
4. Inequality with a common factor6. Three negative and three above 7.
5. Inequality in context3. 0 < x < 4.
6. Discriminant condition11. −5 to 5.
7. Two inequalities together5. −3 to 1.
8. A negative leading coefficientA. B is the upward pattern (or the sign not reversed); C keeps one root; D swaps the roots' signs.

What each wrong answer tells you

They giveWhat it usually meansWhat to do
A, C or D in question 1Gave the region between the roots, one side only, or wrong signs on the roots.Ask them to test x = 0 in the original inequality.
9 or 8 in question 2Included the roots, or gave the gap.List the integers between the roots and cross out the endpoints.
−7 or 7 in question 3Gave the smaller root, or the wrong sign.Ask: in which direction is the interval, and which end is the largest?
8 or 3 in question 4Included the roots, or divided by x.Ask them to test x = −1 and x = 0 in x2 > 7x.
4 or 9 in question 5Included the equality, or used the wrong root.Substitute x = 4: is the area less than 36?
13 or 5 in question 6Included the repeated root, or counted only positive values.Ask what the discriminant is at k = 6.
7 or 9 in question 7Used one inequality only, or included 4 and −4.Draw both solutions on one number line and shade the overlap.
B, C or D in question 8Used the upward pattern or did not reverse the sign, kept one root, or swapped the roots' signs.Test x = 0 and x = 7 in 24 + 2x − x2.

Questions worth asking

Differentiation

A way in for anyone stuck

Stretch

Students learning in English as an additional language

“Inequality” means a statement with < or > rather than =. “Critical value” means a number where the sign can change. “Strict” means that the end values are not included. “Region” here means a stretch of the number line.

WordPlain meaningExample
inequalitya statement that one expression is less than or greater than anotherx2 < 10
critical valuea number where an expression changes signa root of the quadratic
sign diagrama number line showing where an expression is positive or negativeplus, minus, plus
strict inequalityone that uses < or > and excludes the end valuesx > 5
discriminantb2 − 4ac, which tells the number of real rootsnegative: no real roots

Sentence starters for explaining aloud or in writing:

Two things not to say

“Positive means outside.” Say instead: for an upward parabola positive is outside the roots, and the rule flips for a downward one.

“Just take the square root.” Say instead: factorize and use the sign diagram, because both roots matter.

Questions to set

Extra practice in three tiers, including one question from earlier work for spacing. Every answer has been checked.

1Fluency

The idea on its own, with friendly numbers. Set these first.

  1. FindSolve x2 − 9 < 0.
    −3 < x < 3.
  2. FindSolve (x − 1)(x + 4) ≥ 0.
    x ≤ −4 or x ≥ 1.

2In context

The same idea inside a situation, where the first job is deciding what to calculate.

  1. ContextA ball's height is h = 20t − 5t2 metres. For which times is it above 15 m?
    5t2 − 20t + 15 < 0, so 1 < t < 3.
  2. Earlier work (Year 10)Find the roots of x2 − 6x − 16.
    −2 and 8.

3Challenge

Reasoning, generalizing and working backwards.

  1. ReasoningFor which values of m does x2 + mx + 4 > 0 hold for all x?
    m2 < 16, so −4 < m < 4.
  2. Working backwardsA quadratic is negative exactly when −1 < x < 6. Write one such quadratic.
    (x + 1)(x − 6), which is x2 − 5x − 6.

Practicalities

Works on a phone or a shared screen. Nothing a student types is saved or sent anywhere.

The figure works with the keyboard (tab to a slider, then the arrow keys) and by touch. “Show me the steps” gives the same states in words.

No calculator is needed.