Year 11 Extended · Unit 2 · Lesson 5 · teacher page

Teaching: the sine rule and the ambiguous case

The derivation is the point of the first half: the rule is not a fact to memorise but a statement that the height can be found two ways. The ambiguous case then needs the picture of a compass arm.

Geometry and TrigonometryScientific calculator

At a glance. One lesson of about 60 minutes. It assumes the unit circle (lesson 1), right-angled trigonometry and the angle sum of a triangle. Students derive the rule from two right-angled triangles, use it for a side and an angle, and decide how many triangles fit given two sides and a non-included angle. The cosine rule is the next lesson.

Calculator: scientific calculator. A scientific calculator is needed for sines and inverse sines. Degree mode and brackets are the two practical points; the figures give values to check against.

What students will learn

Know

  • The sine rule: a ÷ sin A = b ÷ sin B = c ÷ sin C.
  • The angle must be opposite the side in each pair.
  • sin (180° − x) = sin x.

Understand

  • The rule comes from finding the height of a triangle two ways.
  • Two sides and a non-included angle can fit two triangles.
  • If the given side opposite the angle is at least as long as the other given side, only one fits.

Do

  • Find a missing side with the sine rule.
  • Find a missing angle, and test the second possibility.
  • Decide how many triangles fit.

MYP assessment criteria

Wording paraphrased. What this lesson gives you evidence for, and what to look for:

The one thing to do with the figure

Make students commit before the height appears. In the first figure, ask “Which two expressions equal the height h?” before the readouts are read.

In the second figure, ask “How many triangles for a = 7?” before moving the slider, and ask what the smallest a is that works.

A possible order

5 minWarm-up from the student page, in silence, then answers.
7 minHook: the smoke on the ridge. Collect what students think they need.
10 minFirst figure and key idea: the derivation of the rule.
10 minSecond figure, the warning card and the worked examples; pairs finish the faded example.
5 minThe check. If many choose B, ask what is left for angle C when B = 130°.
18 minYour turn, Levels 1 to 3, at each student's own pace.
5 minSomething to think about, then the exit ticket, question 8.

The answers

Warm-up40°; 55°; 10.
HookTwo angles and the 5 km side fix the triangle; then the third angle follows and the sine rule gives both distances. Two sides and a non-included angle may fit two triangles.
Worked examplesb = 17.5; B = 55.7° or 124.3°.
Faded exampleQ = 33.0°, with only one triangle.
1. How many trianglesC. A would need a shorter than the height; B forgets that the angles must add to less than 180°; D ignores that three measurements are given.
2. Sine rule for a side20.6. 14 × 0.9063 ÷ 0.6157.
3. Sine rule for an angle43.6. sin⁻¹ 0.689.
4. The ambiguous case131.4. 180 − 48.6.
5. When a triangle exists12. 25 × sin 28° = 11.7.
6. A surveying problem103.4. 80 × sin 71° ÷ sin 47°.
7. Sine rule with an obtuse angle21.3. 30 × sin 40° ÷ sin 115°.
8. Reading the ambiguous caseB. A misses the second angle; C is the complement; D leaves out sin 32°.

What each wrong answer tells you

They giveWhat it usually meansWhat to do
A, B or D in question 1 (the check)Thinks the side cannot reach the base, keeps 130° without testing the angle sum, or thinks more is needed.Ask: what is left for angle C if B = 130°?
9.5, 23.9 or 12.7 in question 2Swaps the sines, uses angles, or forgets to divide.Write the pairs p, P and q, Q and then the equation.
0.69, 136.4 or 51.3 in question 3Stops at the sine, gives the obtuse angle, or uses angles.Finish with the inverse key and then test.
48.6, 41.4 or 101.4 in question 4Gives the first angle, the complement, or the third angle.Ask: what other angle has the same sine?
11, 25 or 22 in question 5Rounds down, uses b, or uses cosine.Sketch the triangle and mark the perpendicular height.
61.9, 85.7 or 74.7 in question 6Swaps the sines, or pairs the side with the wrong angle.Find C first and mark each opposite pair in colour.
42.3, 14.0 or 19.3 in question 7Swaps the sines, finds b instead of c, or forgets to divide.Find C from the angle sum first; say: sin 115° is the same as sin 65°.
A, C or D in question 8Stops at the calculator's angle, uses the complement, or drops a sine.Find sin C, then both angles, then test each against 32°.

Questions worth asking

Differentiation

A way in for anyone stuck

Stretch

Students learning in English as an additional language

“Opposite” means across from: side a is across from angle A. “Acute” means less than 90 degrees and “obtuse” means between 90 and 180 degrees. “Ambiguous” means it could be read in two ways. “Perpendicular” means at a right angle.

WordPlain meaningExample
sine rulea side divided by the sine of its opposite angle is the same for all three sidesa ÷ sin A = b ÷ sin B
oppositeacross from: side a is opposite angle Athe side that does not touch the angle
ambiguous casea set of measurements that fits two different trianglestwo sides and an angle not between them
perpendicular heightthe shortest distance from a corner to the opposite sidethe height from C to AB
obtusean angle between 90° and 180°an angle of 120°

Sentence starters for explaining aloud or in writing:

Two things not to say

“The sine rule only works in acute triangles.” It holds for every triangle.

“Always give two answers.” The second angle has to be tested.

Questions to set

Extra practice in three tiers, including one question from earlier work for spacing. Every answer has been checked.

1Fluency

The idea on its own, with friendly numbers. Set these first.

  1. Third angleTwo angles of a triangle are 72° and 51°. Find the third.
    57°.
  2. Sine rulea = 10, A = 30°, B = 90°. Find b.
    20. 10 ÷ 0.5.

2In context

The same idea inside a situation, where the first job is deciding what to calculate.

  1. ContextTwo towers 4 km apart see a fire at angles 55° and 70° to the line between them. How far is the fire from the tower with the 55° angle?
    4 × sin 70° ÷ sin 55° = 4.6 km.
  2. Earlier work (Lesson 4)Solve sin x = 0.5 for 0° to 360°.
    30° and 150°.

3Challenge

Reasoning, generalizing and working backwards.

  1. ReasoningA = 40°, a = 5 and b = 10. How many triangles? Explain.
    None: the height is 10 sin 40° = 6.4, more than 5.
  2. Working backwardsTwo triangles fit with A = 30° and b = 10. Give a value of a that works.
    Any a between 5 and 10, for example 7.

Practicalities

Works on a phone or a shared screen. Nothing a student types is saved or sent anywhere.

Both figures work with the keyboard (tab to a slider, then the arrow keys) and by touch. Under each figure, “Show me the steps” gives the same states in words.

No device? Give each pair a pair of compasses and ask them to draw A = 35°, b = 10 and then swing arcs of different lengths a to see how many triangles close.