Year 10 Standard · Unit 5 · Lesson 1 · teacher page

Teaching: slant height and surface area

Students know Pythagoras and the area of a circle. This lesson asks them to find the right-angled triangle hidden inside a solid, and to see why the length that runs along the surface is not the length they measure straight up.

Geometry and TrigonometryGDC optional

At a glance. One lesson of about 60 minutes. It assumes Pythagoras and the circle area from Year 9. Students find slant heights, then the curved and total surface area of cones and the total surface area of square-based pyramids, leaving π in exact answers.

Calculator: GDC optional. The lesson is done by hand with π left in the answer. The optional section shows GDC users how to enter the whole expression once and not round in the middle.

What students will learn

Know

  • Slant height s = √(r² + h²) for a cone; l = √(h² + (b/2)²) for a face of a square-based pyramid.
  • Cone: curved surface πrs, total πr² + πrs.
  • Square-based pyramid: total b² + 2bl.

Understand

  • The slant height is the hypotenuse of a triangle inside the solid, so it is always longer than the vertical height.
  • The surface of a solid is made of shapes whose measurements are found on the surface, not along its axis.

Do

  • Find a slant height by Pythagoras, in either direction.
  • Find the curved and total surface area of a cone and the total surface area of a pyramid.
  • Work back from a total surface area to a missing length.

MYP assessment criteria

Wording paraphrased. What this lesson gives you evidence for, and what to look for:

The one thing to do with the figure

Settle the hook with the triangle, not a rule. Ask students to set the sliders to a radius and height they choose, then to say which side of the triangle is the strip of straw. Ask: why can the slant never be shorter than the height?

In the second figure, ask where the foot of the slant height l sits on the base. It is the middle of a base edge, so the leg on the base is b/2, not b.

A possible order

5 minWarm-up from the student page, in silence, then answers.
5 minHook: the hat. Collect votes and reasons for the strip length.
12 minFirst figure; key idea; settle the hook; the warning card.
8 minSecond figure; the three worked examples; pairs finish the faded example.
5 minQuestion 1, the check. If many choose A, return to the triangle.
20 minYour turn, Levels 1 to 3, at each student's own pace.
5 minSomething to think about, then the exit ticket, question 9.

The answers

Warm-up25 cm; 16π cm²; 35 cm².
Hook20 cm: √(12² + 16²) = √400.
Worked examples600π cm²; 1200 cm²; 55.0 cm².
Faded example896 cm².
1. Finding the slant heightB. A adds the legs; C subtracts them; D multiplies them.
2. Curved surface of a cone60. s = 10, so πrs = 60π.
3. Slant height of a pyramid face13. √(144 + 25).
4. Total surface area of a pyramid360. 100 + 260.
5. Canvas for a conical tent113.1 m². 36π.
6. Working back to a vertical height15. √(289 − 64).
7. Working back to a slant height8. 7s = 56.
8. A paper party hat817 cm². 260π.
9. Total surface area of a coneD. A uses h instead of s; B leaves out the base; C does both.

What each wrong answer tells you

They giveWhat it usually meansWhat to do
A, C or D in question 1Added, subtracted or multiplied the legs.Draw the triangle and write s² = r² + h² before any number.
48 or 36 in question 2Used the vertical height, or gave the base area.Ask: which length runs along the outside of the cone?
17 or 22 in question 3Added the legs, or used the whole base edge.Mark the foot of the slant on the middle of a base edge.
260 or 340 in question 4Left out the base, or used the vertical height for the faces.List the five faces of the pyramid before calculating.
163.4, 36 or 50.3 in question 5Added the floor, left out π, or gave the floor.Ask whether the floor is covered by canvas.
9 or 33 in question 6Subtracted or added lengths instead of squares.Rearrange Pythagoras: h² = l² − (b/2)².
15 or 56 in question 7Forgot the base, or forgot to divide by r.Write 49π + 7πs = 105π and solve in two steps.
754 or 1131 in question 8Used the vertical height, or added a base the hat does not have.Ask which faces the paper actually covers.
A, B or C in question 9Used h for the curved surface, left out the base, or both.Write the two parts of the surface on separate lines first.

Questions worth asking

Differentiation

A way in for anyone stuck

Stretch

Students learning in English as an additional language

“Slant” means leaning, not straight up. “Vertical height” is straight up from the base. Say “s squared equals r squared plus h squared” aloud so the spoken form is clear, and point to the sides of the triangle as you say it.

WordPlain meaningExample
slant heightthe length of the sloping side from the apex to the edge of the basethe sloping edge of a roof, from the ridge to the gutter
vertical heightthe distance straight up from the base to the apexh in the cone
curved surfacethe part of a cone's surface that is not its baseπrs
total surface areathe area of every face, including the basecurved surface plus base
apexthe point at the top of a cone or pyramidthe tip of the hat
hypotenusethe longest side of a right-angled triangle, opposite the right anglethe side of length 5 in a 3, 4, 5 triangle

Sentence starters for explaining aloud or in writing:

Two things not to say

“Just use the height.” The surface needs the slant height; the height is a leg of the triangle.

“Memorize the formula.” Draw the triangle: the formula comes from it each time.

Questions to set

Extra practice in three tiers, including one question from earlier work for spacing. Every answer has been checked.

1Fluency

The idea on its own, with friendly numbers. Set these first.

  1. Slant heightA cone has radius 20 cm and vertical height 21 cm. Find its slant height.
    29 cm.
  2. Earlier work (Year 9)A cylinder has radius 5 cm and height 8 cm. Find its curved surface area in terms of π.
    80π cm².

2In context

The same idea inside a situation, where the first job is deciding what to calculate.

  1. ContextA pyramid-shaped roof in Kyoto has a square base of edge 18 m and vertical height 12 m. Find the area of its four sloping faces.
    l = 15 m, so 2 × 18 × 15 = 540 m².
  2. Working backA cone with radius 5 cm has curved surface 65π cm². Find its slant height and vertical height.
    s = 13 cm and h = 12 cm.

3Challenge

Reasoning, generalizing and working backwards.

  1. ReasoningA cone's slant height is twice its radius. Show that its curved surface is twice its base area.
    πr(2r) = 2πr², and the base is πr².
  2. OpenFind a cone with radius more than 20 cm and whole-number vertical height whose slant height is also a whole number.
    For example r = 24 and h = 7 give s = 25.

Practicalities

Works on a phone or a shared screen. Nothing a student types is saved or sent anywhere.

Both figures work with the keyboard (tab to a slider, then the arrow keys) and by touch. “Show me the steps” gives the same states in words.

No device? Paper cones and a ruler are enough: students measure the slant side along the paper and the vertical height with a set square. The With a GDC section is optional.