Topic 1.3 · teacher page · both courses, SL and HL

Same start, 51 times apart

Why starting both sequences identically is the only version of this comparison that works.

The one thing to do with the animation

Point out that both sequences are 3, 6 before you run it.

Drawn separately, students explain the gap away: the geometric one must have started higher, or stepped bigger. Starting both at 3, 6 removes every excuse, and by n = 10 it is 30 against 1536.

The y axis is linear on purpose. The arithmetic line lying flat along the bottom is not a flaw in the picture; that is genuinely what the comparison looks like, and a log scale would hide the only thing worth seeing.

Find r by dividing

The commonest wrong start is subtracting consecutive terms, which gives d and sends the whole question into the arithmetic formulas. Divide, and check the same ratio appears twice before committing.

Checking twice also catches sequences that are neither, which do appear in modelling questions where identifying the type is itself the mark.

The answers

1. u₁₀3 × 2⁹ = 1536.
2. S₁₀3(2¹⁰ − 1)/1 = 3069.
3. Sum to infinity4/(1 − 0.5) = 8.

Where the marks go

1 markFinding r by division, with the ratio confirmed on a second pair.

1 markThe n − 1 in the power.

1 markStating |r| < 1 before using the sum to infinity.

What each wrong answer tells you

They giveWhat it means
3072 (Q1)Used rⁿ instead of rⁿ⁻¹. The same off-by-one as 1.2, now in the exponent.
30 (Q1)Used the arithmetic sequence. They subtracted to find the step.
1536 (Q2)Gave the term, not the sum.
2 (Q3)Divided by 2 rather than by 0.5. Worth a reminder that dividing by a half doubles.
7.9922 (Q3)Gave S₁₀. Close enough to look right, which is why the exact limit matters.

Other things they will say

"Why does the sum stop at a number?" Because the terms shrink fast enough that the leftover is always 8rⁿ, which goes to nothing. Show the shortfall shrinking rather than asserting convergence.

"What if r is negative?" The terms alternate in sign, and the sum to infinity still exists if |r| < 1. Worth one example because it looks alarming and is not.

"Is compound interest geometric?" Yes, exactly, and that is the next lesson. Flagging it here makes 1.4 feel like a consequence rather than new material.

A possible order

 What is happening
1Both sequences from the same start. Step to n = 10.
2The two formulas, with r found by division.
3The three questions.
4r < 1, the shrinking shortfall, and the condition on the sum to infinity.
5Set up 1.4: compound interest is this with r = 1 + rate.

Two things not to say

Do not use a logarithmic y axis to fit both sequences on. It makes exponential growth look linear, which is the opposite of the lesson.

Do not introduce the sum to infinity without the |r| < 1 condition in the same breath.

Questions to set

Three tiers, ramping the way practice should: the method on its own, then the method inside something real, then a challenge. Set the tier the class in front of you needs rather than one undifferentiated sheet. Answers are given so these can go straight onto a board.

1Fluency

The method on its own, with friendly numbers. Set these first and move on quickly once they are secure.

  1. nth termu₁ = 5 and r = 3. Find u₆.
    1215
  2. Sum to infinityu₁ = 12 and r = 0.25. Find S∞.
    16

2In context

The same skill inside a real situation, where the first job is working out what is being asked.

  1. Decay in contextA football loses 20% of its bounce height each time. Dropped from 3 m, how high is the fourth bounce?
    3 × 0.8⁴ = 1.2288 m
  2. Compare growthOne savings plan adds 500 baht a month. Another starts at 500 and grows 5% a month. After 24 months, which has paid in more, and by how much?
    Arithmetic 12,000; geometric 500(1.05²⁴ − 1)/0.05 = 22,251 baht. The geometric one, by about 10,251 baht.

3Challenge

Reasoning, working backwards, or spotting an error. These are where the top grades are decided.

  1. Justify convergenceExplain, without the formula, why a geometric series with r = 0.5 cannot exceed twice its first term.
    Each term is half the one before, so the remaining tail is always equal to the term just added. The total therefore closes on 2u₁ and never passes it.
  2. Find r from a sumA geometric series has u₁ = 8 and S∞ = 32. Find r, then explain why r = 1.25 is impossible.
    r = 0.75. With r = 1.25 the terms grow, so no sum exists, and the formula would return a negative total for positive terms.

Practicalities

Works on a phone. Nothing is loaded from any other site, so it runs behind a school firewall, and nothing a student does is saved or sent anywhere.