Equally spaced on a circle, so the rest are rotations.
Sweep n and ask what stays the same.
The roots are always the same distance from the origin and always equally spaced. So one root plus an angle of 2pi/n gives every other, and nobody needs to solve n separate equations.
The conjugate pairing is a reflection, visible as the symmetry about the horizontal axis. That is a far better reason to believe "complex roots come in pairs" than being told it.
With no x^(n-1) term the roots sum to zero, because they are symmetrically placed about the origin. It is free and it catches a wrong angle immediately.
Pair it with the quadratic checks: roots sum to -b/a and multiply to c/a. For 2 +/- 3i that is 4 and 13, both of which can be read straight off the equation.
| 1. Imaginary part of the other root | -3; the conjugate is 2 - 3i. |
| 2. Modulus of each cube root of 8 | 2. |
| 3. Fourth roots, degrees apart | 360/4 = 90. |
1 markOne root found properly, then 2pi/n added for the rest.
1 markArguments given in the required range.
1 markThe conjugate pair stated explicitly for a real polynomial.
| They give | What it means |
|---|---|
| +3 (Q1) | Repeated the same root; the conjugate flips the sign. |
| 2 (Q1) | Gave the real part, which is unchanged. |
| 8 (Q2) | Gave the number rather than the root's modulus. |
| 2.667 (Q2) | Divided by 3 instead of taking a cube root. |
| 120 (Q3) | Used three roots instead of four. |
"Do I solve n equations?" No. One, then rotate. The figure is the argument.
"Why must complex roots pair up?" Because the coefficients are real, so the imaginary parts have to cancel. On the diagram it is a mirror in the horizontal axis.
"What if the coefficients are not real?" Then they need not pair, and the course does not ask. Worth saying so the rule is remembered with its condition.
| What is happening | |
|---|---|
| 1 | Sweep n. What stays the same? |
| 2 | De Moivre, forwards and then backwards for roots. |
| 3 | The cube roots of 8 in full, with the sum-to-zero check. |
| 4 | Conjugate pairs in quadratics and cubics. |
| 5 | A root question given in Cartesian form, converted and solved. |
Do not find each root separately. It is slower, it is error-prone, and it hides the structure.
Do not state the conjugate rule without "with real coefficients". The condition is the whole of it.
Three tiers, ramping the way practice should: the method on its own, then the method inside something real, then a challenge. Set the tier the class in front of you needs rather than one undifferentiated sheet. Answers are given so these can go straight onto a board.
The method on its own, with friendly numbers. Set these first and move on quickly once they are secure.
The same skill inside a real situation, where the first job is working out what is being asked.
Reasoning, working backwards, or spotting an error. These are where the top grades are decided.
Works on a phone. Nothing is loaded from any other site, so it runs behind a school firewall, and nothing a student does is saved or sent anywhere.