Almost everyone is taught that a curve gets closer and closer to its asymptote and never touches it. The first half of that is right. y = (2x + 1)/(x² + 1) has a horizontal asymptote at y = 0 and sits exactly on it at x = −0.5.
An asymptote describes what happens far away. It makes no promise about the middle.
A horizontal asymptote at y = L says: as x runs off to infinity, the outputs approach L. That is all.
A vertical asymptote is different, and that is where the "never touches" idea comes from. y = (2x + 1)/(x − 3) has one at x = 3, because at x = 3 the bottom is zero and the function has no value at all. It cannot be crossed, because there is nothing there to cross.
The same function's horizontal asymptote is y = 2, and that one really is never reached:
So one of these curves crosses its horizontal asymptote and the other cannot, and you can tell which by trying to solve f(x) = L. That takes one line and settles it.
| Feature | What it means | Worked on y = x² − 4x + 1 |
|---|---|---|
| y-intercept | Where the graph meets the y-axis. Put x = 0. | 1 |
| Zeros, or roots | Where it meets the x-axis. Solve f(x) = 0. | 0.27 and 3.73 |
| Vertex | The single turning point of a parabola. | (2, −3) |
| Axis of symmetry | The vertical line through the vertex. | x = 2 |
| Minimum value | The smallest output. For an upward parabola, the vertex's y. | −3 |
Zero, root and x-intercept are the same thing with three names. A zero of the function, a root of the equation and an x-intercept of the graph all mean the same place. Questions switch between them deliberately, and a student who thinks they are three different things will go looking for something that is not there.
The vertex sits midway between the roots. Here (0.27 + 3.73)/2 = 2, which is the axis of symmetry. That is a free check on both answers, and it works for every parabola with two real roots.
Finding where two curves meet is a calculator job and an accuracy trap.
Every feature in this sub-topic has its own tool, and each one finds exactly one answer per go. Knowing that is the difference between finding both roots and finding one.
When you may use it. Applications allows a calculator in every paper, and this sub-topic assumes one. Analysis does not allow one in Paper 1, where the same features come from the algebra: completing the square for a vertex, the formula for roots.
The mark people lose. Finding one root and stopping. Every one of these tools answers once per go, so a question worth two marks for "the zeros" wants you to run it twice. The other one is accuracy: reading 1.6 off the screen when the tool says 1.618 and the question asked for three significant figures. Use the tool's number, not the picture's. And on the Casio, G-SOLVE is SHIFT F5, not F5.
1. For y = x² − 4x + 1, what is the y-coordinate of the vertex?
2. For the same parabola, give the larger root to 2 decimal places.
3. For y = (2x + 1)/(x − 3), what is the equation of the vertical asymptote? Type just the x value.
4. For y = (2x + 1)/(x² + 1), give the maximum value to 3 decimal places.
5. A student says a graph can never meet its asymptote. What is the accurate version?
1 markEach feature found, to the stated accuracy.
1 markEach feature named correctly, where the question asks for a description rather than a number.
1 markAn asymptote given as an equation: x = 3, not 3.
That last one is the cheapest mark lost in this sub-topic. An asymptote is a line, so its answer is an equation. "3" is a number and does not name a line.
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