AA Topic 5.7 · Analysis and Approaches, SL and HL

Three graphs that have to agree

What f′ and f″ look like underneath f, and how to tell which is which when nobody labels them.

Here are f, f′ and f″ for the same function. Move the line and watch what happens at the same x in all three. Then hide the labels and see whether you could still tell them apart, because that is what the question usually asks.

x = −0.30
–f(x)
–f′(x)
–f″(x)

Watch x = 1, x = 2 and x = 3. Something happens at each one, in a different graph each time.

How to tell them apart

For f(x) = x³ − 6x² + 9x:

at x =123
fmaximum, 4inflexion, 2minimum, 0
f′crosses zerominimum, −3crosses zero
f″−6crosses zero6

The inflexion at x = 2 is not a turning point. The gradient there is −3, nowhere near zero. f″ is zero, so the bend changes, but the curve carries on downwards throughout. That is a point of inflexion with a non-zero gradient, and it is the case most often missed.

Reading one graph from another

A very common question gives you the graph of f′ and asks about f. Work from the sign and the zeros:

If f′ isthen f is
above the axisincreasing
crossing the axis downwardsat a maximum
crossing the axis upwardsat a minimum
at its own minimum or maximumat a point of inflexion
touching the axis without crossingat a stationary point of inflexion

Your turn

1. For f(x) = x³ − 6x² + 9x, find f″(1).

2. The graph of f′ has a minimum at x = 2. What is happening to f at x = 2?

3. Give the y coordinate of the point of inflexion.

Where the marks go

When sketching f′ from f, get the zeros in the right places first. Everything else follows, and the zeros are where the marks are.

Say which feature of which graph you are using. "f′ has a minimum at x = 2, so f has a point of inflexion there" is a complete reason; pointing at a picture is not.

Degrees drop by one each time. If you sketch f′ of a cubic as another cubic, something has gone wrong before you started.

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